10x^2+12=34x

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Solution for 10x^2+12=34x equation:



10x^2+12=34x
We move all terms to the left:
10x^2+12-(34x)=0
a = 10; b = -34; c = +12;
Δ = b2-4ac
Δ = -342-4·10·12
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-26}{2*10}=\frac{8}{20} =2/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+26}{2*10}=\frac{60}{20} =3 $

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